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The PN Junction

Start here. Join two doped blocks, watch a barrier build itself, then bias it both ways and see why only one direction conducts.

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A PN junction is what forms when P-type and N-type semiconductor meet: diffusion strips a thin region of mobile carriers, the fixed ions left behind create a field that stops further diffusion, and that self-built barrier is what makes the junction conduct in one direction only.

Before the junction: two neutral blocks

Pure silicon has four valence electrons and conducts poorly. Doping adds impurity atoms: a pentavalent donor such as phosphorus contributes a spare electron (N-type), and a trivalent acceptor such as boron leaves a vacancy that behaves as a positive carrier (P-type).

Both blocks start electrically neutral. Every mobile carrier is balanced by the fixed impurity ion that supplied it. This is the fact the whole rest of the argument turns on.

Majority carriers
Electrons in N-type, holes in P-type. Their number is set by the doping and barely changes with temperature.
Minority carriers
Holes in N-type, electrons in P-type. Thermally generated, so their number roughly doubles every 10 °C — which is where every temperature-dependent term in this subject comes from.

The barrier builds itself

  1. 1Contact. A huge concentration gradient exists at the boundary.
  2. 2Diffusion. Electrons cross into P and holes into N, purely from the gradient — the same statistics that spreads ink in water. Near the junction they recombine.
  3. 3Exposed ions. Each departed carrier leaves behind a *fixed* ion: positive donors on the N side, negative acceptors on the P side. These are locked into the lattice and cannot follow.
  4. 4A field appears. The exposed charge creates an electric field pointing from N to P, which pushes electrons back toward N and holes back toward P — against the diffusion.
  5. 5Equilibrium. Each carrier that crosses strengthens the field opposing the next. The process is self-limiting and settles where diffusion current exactly cancels drift current.

The stripped region is the depletion region — depleted of *mobile* carriers, though full of fixed charge. The potential across it is the built-in potential V₀, about 0.7 V in silicon and 0.3 V in germanium.

You cannot measure V₀ with a voltmeter. Attaching probes creates two more junctions whose potentials exactly cancel it — which is fortunate, because a battery you could make out of a diode would violate the second law of thermodynamics.

Reverse bias: help the field

Connect the positive terminal to N and the negative to P. The applied voltage adds to the built-in field. Majority carriers are pulled away from the junction, the depletion region widens, and the barrier gets taller. Almost nothing crosses.

What remains is the reverse saturation current I₀ — nanoamps, produced by thermally generated minority carriers that the field is happy to sweep across. It is nearly independent of the applied voltage and roughly doubles per 10 °C, which is why it matters far more in a hot circuit than a cold one.

Increase the reverse voltage enough and the junction breaks down, by tunnelling (Zener, below ~5 V) or by impact ionisation (avalanche, above it). Breakdown is not destruction — a Zener diode is built to live there — provided the power dissipated is limited.

Forward bias: fight the field

Connect positive to P and negative to N. Now the applied voltage opposes the built-in field. The depletion region narrows, the barrier drops, and the fraction of carriers with enough energy to cross rises — as a Boltzmann factor, so exponentially.

That exponential is why the diode appears to have a threshold. At 0.5 V the current is microamps, at 0.7 V it is milliamps, at 0.8 V amps. Nothing switches on at 0.7 V; that is simply where an exponential becomes visible on a linear axis. Every extra ~60 mV multiplies the current by ten.

Reverse biasForward bias
Applied fieldadds to built-in fieldopposes built-in field
Depletion regionwidernarrower
Barrier heighthigherlower
Current~nA, nearly constantexponential in V
Carried byminority carriersmajority carriers

What the junction gets used for

  • Rectification — one-way conduction turns AC into pulsating DC. The first module after this one.
  • Voltage reference — reverse breakdown occurs at a sharply defined voltage, which is a Zener regulator.
  • Amplification — two junctions back to back is a BJT, and the base-emitter junction's exponential is where its transconductance comes from.
  • Light — recombination across the junction can emit a photon (LED); absorbed photons can create carriers (photodiode, solar cell).
  • Variable capacitance — the depletion region is an insulator between two conductors, and reverse bias changes its width. That is a varactor, and it tunes radios.

The numbers you will be asked for

Shockley diode equation

I = I₀·(e^(V / (η·V_T)) − 1)

η is 1–2 depending on the material and current range.

Thermal voltage

V_T = kT/q ≈ 26 mV at 300 K

The scale factor in the exponential, and the source of most temperature dependence.

Built-in potential

V₀ = V_T · ln(N_A·N_D / n_i²)

Rises with doping; falls as temperature raises the intrinsic concentration n_i.

Depletion width

W ∝ √(V₀ − V)

Forward bias shrinks it, reverse bias widens it — the basis of the varactor.

Advantages and disadvantages

Advantages

  • The asymmetry is intrinsic to the junction — nothing is added to create it.
  • Breakdown voltage can be set precisely by choosing the doping.
  • The same structure gives rectifiers, references, detectors, emitters and variable capacitors.
  • The exponential I-V is what makes transistor transconductance predictable across decades of current.

Disadvantages

  • A forward-biased junction always drops ~0.7 V, which is wasted power in a rectifier and dominant at low voltages.
  • Reverse leakage roughly doubles every 10 °C, so a design that works cold can fail hot.
  • Stored charge must be swept out before the junction can block, limiting switching speed (reverse recovery).
  • The exponential means a small voltage error is a large current error, so diodes are driven by current, not voltage.

Watch it work

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Check yourself

question 1 / 5

One question at a time. Pick an answer to see why it is right or wrong, then move on — there is no score to keep and nothing is saved.

Both blocks start neutral. Where does the electric field across the depletion region come from?
Why does the diffusion stop rather than continuing until the carriers are evenly mixed?
A diode is often described as 'switching on at 0.7 V'. What is actually happening at 0.7 V?
Reverse leakage current roughly doubles for every 10 °C rise. Why is temperature so much more important in reverse than in forward?
Why can you not measure the 0.7 V built-in potential by putting a voltmeter across an unbiased diode?

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5 still unanswered — the dots above jump straight to them.

 

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