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Series and Parallel Resonance

A passive circuit developing 500 V from a 10 V source, with no amplifier in it — and KVL never violated.

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At ω₀ = 1/√(LC) the inductive and capacitive reactances cancel exactly, leaving a purely resistive circuit — which in series means minimum impedance and voltages Q times the source, and in parallel means maximum impedance and a circulating current Q times the line current.

Why cancellation happens

Inductive reactance grows with frequency and capacitive reactance shrinks, and they carry opposite signs. At ω₀ = 1/√(LC) they are equal and opposite. Note what is absent from that expression: resistance does not set the resonant frequency.

Series resonance

Cancelling reactances leave only R, so impedance dips to its minimum and the circuit is purely resistive — voltage and current in phase. Minimum impedance means maximum current, making it an *acceptor* circuit.

That current flows through both reactances, and each develops Q times the source voltage across it. At Q = 50, a 10 V source produces 500 V across the inductor and 500 V across the capacitor. KVL holds — they are in antiphase and cancel — but each component individually sees the full magnified voltage, which is what destroys capacitors.

Q and bandwidth

Q is the ratio of energy stored to energy lost per cycle — ω₀L/R for a series circuit. It sets how sharp the resonance is, and bandwidth = ω₀/Q, so selectivity and bandwidth are one number expressed two ways.

QBandwidthCharacter
High (low R)NarrowSelective, slow to settle, large magnification
Low (high R)BroadTolerant, quick, little magnification

Parallel resonance

The exact dual. Impedance is maximum at ω₀, so line current is minimum — a *rejector* circuit that blocks one frequency and passes the rest. And the dual of voltage magnification appears: the current circulating inside the LC tank is Q times the current drawn from the supply.

Where it is wanted

A tuned circuit selects one radio station and attenuates its neighbours; turning the dial changes C to move ω₀. Selectivity is Q — but too high a Q narrows the passband enough to cut the sidebands carrying the audio, so a tuner is a deliberate compromise between selectivity and fidelity.

Where it is not

  • Cable capacitance resonates with transformer inductance somewhere, and if a harmonic lands there the voltage magnifies.
  • Power-factor correction capacitors resonate with supply inductance — which is why they are fitted with detuning reactors.
  • Any accidental LC in a layout has an ω₀ and a Q whether anyone designed them or not.

The same mathematics governs bridges, rotors and wings, with mass for L, compliance for C and damping for R. Resonance is not an electrical phenomenon — it is what any second-order system does.

The numbers you will be asked for

Resonant frequency

ω₀ = 1/√(LC) · f₀ = 1/(2π√(LC))

Series Q

Q = ω₀L / R = (1/R)·√(L/C)

Parallel Q

Q = R / ω₀L = R·√(C/L)

Bandwidth

BW = ω₀ / Q

Voltage magnification

V_L = V_C = Q · V_source

Impedance at resonance

series: Z = R · parallel: Z = L/(RC)

Watch it work

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Check yourself

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One question at a time. Pick an answer to see why it is right or wrong, then move on — there is no score to keep and nothing is saved.

Does resistance affect the resonant frequency?
A 10 V source produces 500 V across the inductor of a series resonant circuit. Is KVL violated?
A series resonant circuit has minimum impedance at ω₀. What does a parallel one do?
Why are power-factor correction capacitors fitted with detuning reactors?

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