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Amplitude Modulation

Two thirds of a broadcast transmitter's power carries no information at all — and the reason that was the right decision is in the receiver, not the transmitter.

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Amplitude modulation multiplies the message onto the carrier's size, producing a carrier plus two mirror-image sidebands over twice the message bandwidth — and even at full modulation two thirds of the transmitted power is carrier, which carries no information at all.

The spectrum

Expanding A_c[1 + m·cos(ω_m t)]·cos(ω_c t) with the product-to-sum identity gives three components: the carrier at f_c, and sidebands at f_c ± f_m.

So AM occupies twice the message bandwidth. A 5 kHz audio signal needs 10 kHz of spectrum, which is why AM broadcast channels are spaced at 9 or 10 kHz and why AM sounds the way it does.

Modulation index

m is the ratio of message amplitude to carrier amplitude. Larger m puts more power into the sidebands — the only part carrying information — so broadcasters compress their audio to keep it high.

mEnvelopeSideband share of power
0.3Shallow swing4.3%
0.5Moderate11%
1.0Touches zero33%
>1.0Folds through zeroDistortion, not more information

Past m = 1 the envelope tries to go negative and an envelope detector rectifies it, folding the peaks back. The distortion is irrecoverable, and the resulting splatter into adjacent channels makes it a licensing violation rather than merely a quality problem.

The power problem

Total power is P_c(1 + m²/2). Even at m = 1 the carrier takes two thirds and carries nothing. At realistic speech levels it is closer to 90%. A 50 kW AM transmitter radiates 33 kW of pure carrier.

Trimming the waste

SchemeWhat is sentBandwidthReceiver
AM (DSB-LC)Carrier + both sidebands2 f_mDiode envelope detector
DSB-SCBoth sidebands only2 f_mCoherent, needs carrier recovery
SSBOne sideband onlyf_mCoherent, plus a BFO
VSBOne sideband + a trace of the other≈ 1.25 f_mPartly coherent — used for TV video

The two sidebands are mirror images, so one is genuinely redundant. SSB gets the same message through in half the bandwidth at a fraction of the power, which is why amateur and marine HF use it.

Why broadcast AM kept the carrier anyway

Because the carrier is present, the message is recovered by a diode, a capacitor and a resistor — no local oscillator, no phase synchronisation. That is why a crystal set works with no power supply at all.

The design traded transmitter efficiency for receiver simplicity, which was exactly right when there was one transmitter and a million receivers. It is an economic argument, not a technical one.

AM's other weakness

Most natural and man-made interference — lightning, brush motors, ignition systems — is amplitude noise. AM puts its message in exactly that quantity, so the receiver cannot separate them. That is the crackle, and it is structural.

The numbers you will be asked for

AM signal

s(t) = A_c[1 + m·cos(ω_m t)]·cos(ω_c t)

Modulation index

m = A_m / A_c

must stay ≤ 1

Bandwidth

B = 2 f_m

Total power

P_t = P_c(1 + m²/2)

Efficiency

η = m² / (2 + m²)

33% at m = 1

Index from envelope

m = (V_max − V_min)/(V_max + V_min)

Watch it work

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Check yourself

question 1 / 4

One question at a time. Pick an answer to see why it is right or wrong, then move on — there is no score to keep and nothing is saved.

At full modulation (m = 1), how is an AM transmitter's power divided?
Given the power waste, why did broadcast AM transmit the carrier anyway?
What happens if the modulation index exceeds 1?
Why does AM crackle in a thunderstorm when FM does not?

0 / 4

4 still unanswered — the dots above jump straight to them.