Shear Force and Bending Moment Diagrams
Cut the beam and ask what holds the piece up. Then two calculus relations turn drawing the diagrams into integrating them.
Skip to the animationCutting a beam at a section reveals the internal shear force and bending moment that hold the severed piece in equilibrium — and because dV/dx = −w and dM/dx = V, the two diagrams are successive integrations of the load, with the maximum moment wherever the shear crosses zero.
Why the diagrams exist
A beam in overall equilibrium tells you nothing about any particular cross-section. Internal forces vary along the length and the design must survive the worst of them, so the diagrams exist to locate the maximum — not to be drawn for their own sake.
The cut
- 1Sever the beam at the section of interest and discard one side.
- 2The remaining piece was in equilibrium before, so it must be after.
- 3Vertical forces must sum to zero — the cut face supplies the shear force.
- 4Moments must sum to zero — the cut face supplies the bending moment.
That is the entire method. Everything else is bookkeeping about which loads fall on which side of the cut.
The calculus relations
Load, shear and moment are linked: dV/dx = −w and dM/dx = V. So the shear diagram is the integral of the load, and the moment diagram is the running area under the shear diagram.
- The slope of the shear diagram at any point is the load intensity there.
- The slope of the moment diagram is the shear force there.
- Therefore the maximum moment occurs where the shear crosses zero — which finds the critical section without solving anything.
Shapes you can predict before starting
| Load | Shear diagram | Moment diagram |
|---|---|---|
| Point load | Step change | Kink — slope changes abruptly |
| Uniform load (UDL) | Linear slope | Parabolic |
| Triangular load | Parabolic | Cubic |
| Applied point moment | No change | Step change |
| No load | Constant | Linear |
The step in the moment diagram caused by an applied point moment is the one most often missed. Knowing the expected shape before you compute anything is the cheapest available error check.
Point of contraflexure
Where the bending moment changes sign, the curvature reverses — the beam stops sagging and starts hogging. Sagging puts the bottom fibres in tension; hogging puts the top ones there.
Concrete is weak in tension and steel is placed where the tension is, so this point decides where reinforcement moves from the bottom of a continuous beam to the top over its supports. Getting it wrong puts the steel in the compression zone, where it does very little.
What the diagrams feed
M_maxgoes intoσ = My/Iand sizes the section.V_maxgives the shear stress, which usually governs only for short, deep beams.M(x)is integrated twice to get the deflection, so the moment diagram is that calculation's raw material.
The whole treatment assumes small deflections and a beam long relative to its depth. A deep beam distributes load quite differently, and beam theory should not be applied to it.
The numbers you will be asked for
- Load-shear relation
dV/dx = −w
- Shear-moment relation
dM/dx = V
- Cantilever, tip load
V = W (constant) · M_max = WL
- Simply supported, central load
M_max = WL / 4
- Simply supported, UDL
M_max = wL² / 8
- Cantilever, UDL
M_max = wL² / 2
Watch it work
Check yourself
question 1 / 4
One question at a time. Pick an answer to see why it is right or wrong, then move on — there is no score to keep and nothing is saved.