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Columns and Buckling

The one failure mode that is not about strength at all. Euler's formula contains no yield stress, which is why a stronger steel buys you nothing.

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Buckling is a stability failure rather than a strength failure: a slender column collapses sideways at P_cr = π²EI/Lₑ², a load that depends on stiffness and geometry and contains no yield stress at all — which is why a stronger steel buys no extra capacity.

A different kind of failure

A short block in compression crushes when the stress reaches yield. A slender strut never gets there: it bows sideways and collapses at a stress the material could carry comfortably.

The question changes form too. Not "is the stress acceptable" but "what happens after a small disturbance" — does the strut return to straight, or does the bow grow? That is a stability question, and it needs its own analysis.

Euler's critical load

  1. 1Below the critical load, a sideways disturbance is resisted and the strut springs back. Stable.
  2. 2At the critical load, straight and slightly bent require the same load. The strut is indifferent.
  3. 3Above it, any disturbance grows rather than decaying, and collapse follows.
  4. 4Solving the resulting differential equation gives P_cr = π²EI/Lₑ².

Look at what the formula does not contain: the yield stress. All structural steels have E ≈ 200 GPa regardless of grade, so specifying high-strength steel for a slender column buys nothing at all. The gain has to come from I or from a shorter effective length.

Effective length

End conditionsEffective length LₑRelative capacity
Both ends pinnedL1.0 — the reference case
Both ends fixed0.5 L4.0
One fixed, one pinned0.7 L≈ 2.0
Fixed at the base, free at the top2 L0.25

Since P_cr ∝ 1/Lₑ², the range from fixed-fixed to fixed-free spans a factor of sixteen for the same strut, the same material and the same section.

The practical caution is that real connections are semi-rigid. A bolted end plate is neither pinned nor fixed, and claiming full fixity from a joint that cannot deliver it is unconservative in a failure mode that gives no warning.

The weakest axis governs

A column buckles about the axis with the smallest I — never the one you were designing for. An I-section is excellent in bending about its strong axis and a poor column unless its weak axis is braced.

A circular hollow section has the same I in every direction, which is why it is the natural choice for a free-standing column. Bracing exists precisely to shorten the effective length about the weak axis, and it is why a slender column with mid-height restraint carries four times as much.

Where Euler's formula is wrong

Extrapolated to a short column, Euler's formula predicts a buckling stress above the yield stress — which the material cannot reach, so it crushes first. The formula is valid only above a critical slenderness ratio.

  • Rankine's formula blends the crushing and buckling regimes into one expression.
  • Design codes use curves fitted to test data, with separate curves for different section types and manufacturing routes.
  • Slenderness ratio Lₑ/k is the parameter that decides which regime a column is in, where k is the radius of gyration.

Why real columns are weaker still

ImperfectionEffect
Initial crookednessNo rolled section is perfectly straight; the bow starts before the load arrives
Load eccentricityNever applied exactly on the axis, so a moment exists from the start
Residual stressesLeft by rolling and welding; parts of the section yield early
Accidental lateral loadWind, impact, construction tolerance

All of them push the same way, so measured capacities sit consistently below the theoretical curve. Buckling also gives no warning — no yielding, no cracking, no visible sag — which is why column safety factors are the largest in the subject.

The numbers you will be asked for

Euler critical load

P_cr = π²EI / Lₑ²

Critical stress

σ_cr = π²E / (Lₑ/k)²

Radius of gyration

k = √(I / A)

Slenderness ratio

λ = Lₑ / k

Rankine's formula

P = σc·A / (1 + a·λ²)

blends crushing and buckling

Watch it work

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Check yourself

question 1 / 4

One question at a time. Pick an answer to see why it is right or wrong, then move on — there is no score to keep and nothing is saved.

Specifying a higher-grade steel for a slender column. What does it buy?
A column fixed at both ends against one pinned at both ends. How much more load does it carry?
Which axis does a column buckle about?
Why do measured column capacities sit below Euler's prediction?

0 / 4

4 still unanswered — the dots above jump straight to them.