Principal Stresses and Mohr's Circle
Stress at a point depends on the plane you ask about. One circle answers every plane at once — and then two failure theories disagree by fifteen per cent.
Skip to the animationStress at a point depends on the plane you ask about, and the transformation equations trace a circle — so principal stresses, maximum shear and the planes they act on can all be read from one drawing, which is what lets a combined stress state be compared against a uniaxial test result.
Stress depends on the plane
Cut through a point on one plane and you get one pair of stresses; cut on another and you get a different pair. Nothing about the loading changed — only the question. So "the stress here is 80 MPa" is an incomplete statement.
A two-dimensional stress state takes three numbers: σx, σy and τxy. Everything on any other plane follows from those three.
Principal planes
The transformation equations are sinusoidal in 2θ, so a full cycle takes 180° of physical rotation. Where the direct stress reaches its maximum, the shear stress is exactly zero — those are the principal planes, and the values there are the principal stresses σ₁ and σ₂.
The circle
Squaring and adding the transformation equations eliminates the angle and leaves the equation of a circle. Every plane through the point maps to one point on it, and rotating the physical plane by θ moves you 2θ around the circle — which is why it closes after 180°.
| Feature of the circle | What it means |
|---|---|
| Centre, on the σ axis | The average direct stress, (σx + σy)/2 |
| Radius | The maximum shear stress |
| Where it crosses the σ axis | σ₁ and σ₂, the principal stresses |
| Top and bottom of the circle | Planes of maximum shear, 45° from the principal planes |
| Angle around the circle | Twice the physical rotation |
Because the top of the circle is 90° around from the axis crossings, τ_max acts on planes 45° from the principal planes. That single geometric fact explains slip bands, torsional fractures and the 45° shear failure of a ductile tensile specimen.
Pure shear
Pure shear has zero direct stress on the reference planes, so the circle is centred on the origin and the principal stresses are ±τ. A twisted shaft therefore carries equal tension and compression on planes at 45°.
Brittle materials fail on the tension plane and crack in a 45° helix; ductile ones fail in shear and break flat across the section. Twisting a stick of chalk demonstrates the first in about a second.
Why any of this is needed
Material data comes from a uniaxial test: one stress, one direction, one number. A real component is under a combined state produced by bending, torsion and axial load together. The bridging question — which combination is as severe as the tensile yield stress — is what a failure theory answers, and Mohr's circle supplies its inputs.
Failure theories
| Theory | Criterion | Suits | Allows in pure shear |
|---|---|---|---|
| Maximum shear stress (Tresca) | τ_max = σy/2 | Ductile metals; simple and conservative | 0.500 σy |
| Distortion energy (von Mises) | Energy of shape change | Ductile metals; matches test data best | 0.577 σy |
| Maximum principal stress (Rankine) | σ₁ = σut | Brittle materials — failure is tensile | 1.000 σut |
The 15% gap between Tresca and von Mises is not academic when the factor of safety is 1.5. And using a ductile theory on a brittle material — or the reverse — is a genuine design error, not a matter of preference.
The three-dimensional caution
Two-dimensional analysis assumes the third principal stress is zero. That is fine for a free surface, which is where the maximum stress usually is — but in a thick pressure vessel or a rolling contact, all three are significant and the two-dimensional circle understates the shear.
The numbers you will be asked for
- Principal stresses
σ₁,₂ = (σx+σy)/2 ± √[((σx−σy)/2)² + τxy²]
- Maximum shear
τ_max = (σ₁ − σ₂) / 2
- Principal angle
tan 2θ = 2τxy / (σx − σy)
- Circle centre and radius
C = (σx+σy)/2 · R = τ_max
- Von Mises stress
σ_v = √(σ₁² − σ₁σ₂ + σ₂²)
Watch it work
Check yourself
question 1 / 4
One question at a time. Pick an answer to see why it is right or wrong, then move on — there is no score to keep and nothing is saved.